Write a program to find whether the given number is an armstrong number.
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Source Code
#include <stdio.h>
int is_armstrong (int num)
{
int sum = 0, temp, remainder;
temp = num;
while( temp != 0 )
{
/* Get the digit */
remainder = temp % 10;
/* calculate cube and sum up */
sum = sum + (remainder * remainder * remainder);
/* Shift right by one digit */
temp = temp / 10;
}
if ( num == sum ) {
return 1; /* armstrong number */
} else {
return 0; /* not armstrong number */
}
}
/* Program to check if the number is an armstrong number */
/* Enable only one main() during compilation */
int main(int argc, char *argv[])
{
int number;
printf ("Enter an integer: ");
scanf ("%d",&number);
if ( is_armstrong(number) ) {
printf ("%d is an armstrong number.\n", number);
} else {
printf ("%d is not an armstrong number.\n", number);
}
return 0;
}
/* Printing Armstrong number series */
int main(int argc, char *argv[])
{
int range;
printf ("Enter Max range: ");
scanf ("%d", &range);
printf ("Printing armstrong numbers from 0 - %d\n", range);
for (number = 0; number <= range; number++) {
if ( is_armstrong(number) ) {
printf ("%d, ", number);
}
}
return 0;
}
Output
Enter an integer: 153
153 is an armstrong number.
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